8x2+14x+3=0.

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Solution for 8x2+14x+3=0. equation:



8x^2+14x+3=0.
a = 8; b = 14; c = +3;
Δ = b2-4ac
Δ = 142-4·8·3
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-10}{2*8}=\frac{-24}{16} =-1+1/2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+10}{2*8}=\frac{-4}{16} =-1/4 $

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