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8x^2+168=80x
We move all terms to the left:
8x^2+168-(80x)=0
a = 8; b = -80; c = +168;
Δ = b2-4ac
Δ = -802-4·8·168
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-32}{2*8}=\frac{48}{16} =3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+32}{2*8}=\frac{112}{16} =7 $
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