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8x^2+17x=136
We move all terms to the left:
8x^2+17x-(136)=0
a = 8; b = 17; c = -136;
Δ = b2-4ac
Δ = 172-4·8·(-136)
Δ = 4641
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{4641}}{2*8}=\frac{-17-\sqrt{4641}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{4641}}{2*8}=\frac{-17+\sqrt{4641}}{16} $
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