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8x^2+21=-59x
We move all terms to the left:
8x^2+21-(-59x)=0
We get rid of parentheses
8x^2+59x+21=0
a = 8; b = 59; c = +21;
Δ = b2-4ac
Δ = 592-4·8·21
Δ = 2809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2809}=53$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(59)-53}{2*8}=\frac{-112}{16} =-7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(59)+53}{2*8}=\frac{-6}{16} =-3/8 $
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