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8x^2+25x+13=0
a = 8; b = 25; c = +13;
Δ = b2-4ac
Δ = 252-4·8·13
Δ = 209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{209}}{2*8}=\frac{-25-\sqrt{209}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{209}}{2*8}=\frac{-25+\sqrt{209}}{16} $
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