8x2+25x-10=0

Solution for 8x2+25x-10=0 equation:

8x^2+25x-10=0

a = 8; b = 25; c = -10;
Δ = b2-4ac
Δ = 252-4·8·(-10)
Δ = 945
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{945}=\sqrt{9*105}=\sqrt{9}*\sqrt{105}=3\sqrt{105}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-3\sqrt{105}}{2*8}=\frac{-25-3\sqrt{105}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+3\sqrt{105}}{2*8}=\frac{-25+3\sqrt{105}}{16}
$