8x2+3.5x-15=0

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Solution for 8x2+3.5x-15=0 equation:



8x^2+3.5x-15=0
a = 8; b = 3.5; c = -15;
Δ = b2-4ac
Δ = 3.52-4·8·(-15)
Δ = 492.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3.5)-\sqrt{492.25}}{2*8}=\frac{-3.5-\sqrt{492.25}}{16} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3.5)+\sqrt{492.25}}{2*8}=\frac{-3.5+\sqrt{492.25}}{16} $

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