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8x^2+30x+25=0
a = 8; b = 30; c = +25;
Δ = b2-4ac
Δ = 302-4·8·25
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-10}{2*8}=\frac{-40}{16} =-2+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+10}{2*8}=\frac{-20}{16} =-1+1/4 $
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