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8x^2+32x-4=-2
We move all terms to the left:
8x^2+32x-4-(-2)=0
We add all the numbers together, and all the variables
8x^2+32x-2=0
a = 8; b = 32; c = -2;
Δ = b2-4ac
Δ = 322-4·8·(-2)
Δ = 1088
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1088}=\sqrt{64*17}=\sqrt{64}*\sqrt{17}=8\sqrt{17}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-8\sqrt{17}}{2*8}=\frac{-32-8\sqrt{17}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+8\sqrt{17}}{2*8}=\frac{-32+8\sqrt{17}}{16} $
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