8x2+33x+7=0

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Solution for 8x2+33x+7=0 equation:



8x^2+33x+7=0
a = 8; b = 33; c = +7;
Δ = b2-4ac
Δ = 332-4·8·7
Δ = 865
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-\sqrt{865}}{2*8}=\frac{-33-\sqrt{865}}{16} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+\sqrt{865}}{2*8}=\frac{-33+\sqrt{865}}{16} $

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