8x2+4-16=-x

Solution for 8x2+4-16=-x equation:

8x^2+4-16=-x

We move all terms to the left:

8x^2+4-16-(-x)=0

We add all the numbers together, and all the variables

8x^2-(-1x)+4-16=0

We add all the numbers together, and all the variables

8x^2-(-1x)-12=0

We get rid of parentheses

8x^2+1x-12=0

We add all the numbers together, and all the variables

8x^2+x-12=0

a = 8; b = 1; c = -12;
Δ = b2-4ac
Δ = 12-4·8·(-12)
Δ = 385
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{385}}{2*8}=\frac{-1-\sqrt{385}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{385}}{2*8}=\frac{-1+\sqrt{385}}{16}
$