8x2+40x=238

Solution for 8x2+40x=238 equation:

8x^2+40x=238

We move all terms to the left:

8x^2+40x-(238)=0

a = 8; b = 40; c = -238;
Δ = b2-4ac
Δ = 402-4·8·(-238)
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-96}{2*8}=\frac{-136}{16}
=-8+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+96}{2*8}=\frac{56}{16}
=3+1/2
$