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8x^2+45x-18=0
a = 8; b = 45; c = -18;
Δ = b2-4ac
Δ = 452-4·8·(-18)
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2601}=51$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-51}{2*8}=\frac{-96}{16} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+51}{2*8}=\frac{6}{16} =3/8 $
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