8x2+45x=18

Solution for 8x2+45x=18 equation:

8x^2+45x=18

We move all terms to the left:

8x^2+45x-(18)=0

a = 8; b = 45; c = -18;
Δ = b2-4ac
Δ = 452-4·8·(-18)
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2601}=51$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-51}{2*8}=\frac{-96}{16}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+51}{2*8}=\frac{6}{16}
=3/8
$