8x2+5x-3=0

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Solution for 8x2+5x-3=0 equation: 



8x^2+5x-3=0

a = 8; b = 5; c = -3;
Δ = b2-4ac
Δ = 52-4·8·(-3)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-11}{2*8}=\frac{-16}{16}
=-1
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+11}{2*8}=\frac{6}{16}
=3/8
$

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