If it's not what You are looking for type in the equation solver your own equation and let us solve it.
8x^2+6x-20=0
a = 8; b = 6; c = -20;
Δ = b2-4ac
Δ = 62-4·8·(-20)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-26}{2*8}=\frac{-32}{16} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+26}{2*8}=\frac{20}{16} =1+1/4 $
| 5x2+14x-10=0 | | 14x2+4x-3=0 | | 15x2-7x-1=0 | | 9x2-10x+11=0 | | 12x2+18x+18=0 | | x2+20x-10=0 | | 11x2+4x-3=0 | | 18x2+12x-15=0 | | 14x2+19x-8=0 | | 16x2-13x-2=0 | | 16x2-15x+8=0 | | 19x2+7x-4=0 | | 6x2+17x+7=0 | | 5x2+4x+2=0 | | 5x2+18x+8=0 | | 4x2+11x-14=0 | | 17x2+17x-1=0 | | 10x2-19x-6=0 | | 18x2+11x-7=0 | | 16x2-15x-10=0 | | 6x2-15x-4=0 | | 19x2+7x+10=0 | | 694/12=57r9 | | 4(2x+6)=32(2x) | | 3(2x-4)-5=3 | | 6a+7a=-11 | | 8+4+6=6x7-4 | | 5x-x=9 | | (x+3/8)x2=4.7 | | +2(3y-4)=42 | | 2(x+3)+3x=5(x+1) | | -3x+4=7x-24 |