8x2+7x-75=0

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Solution for 8x2+7x-75=0 equation:



8x^2+7x-75=0
a = 8; b = 7; c = -75;
Δ = b2-4ac
Δ = 72-4·8·(-75)
Δ = 2449
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{2449}}{2*8}=\frac{-7-\sqrt{2449}}{16} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{2449}}{2*8}=\frac{-7+\sqrt{2449}}{16} $

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