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8x^2+7x=2
We move all terms to the left:
8x^2+7x-(2)=0
a = 8; b = 7; c = -2;
Δ = b2-4ac
Δ = 72-4·8·(-2)
Δ = 113
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{113}}{2*8}=\frac{-7-\sqrt{113}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{113}}{2*8}=\frac{-7+\sqrt{113}}{16} $
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