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8x^2+9x+2=1
We move all terms to the left:
8x^2+9x+2-(1)=0
We add all the numbers together, and all the variables
8x^2+9x+1=0
a = 8; b = 9; c = +1;
Δ = b2-4ac
Δ = 92-4·8·1
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-7}{2*8}=\frac{-16}{16} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+7}{2*8}=\frac{-2}{16} =-1/8 $
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