8x2-16x-10=0

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Solution for 8x2-16x-10=0 equation:



8x^2-16x-10=0
a = 8; b = -16; c = -10;
Δ = b2-4ac
Δ = -162-4·8·(-10)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-24}{2*8}=\frac{-8}{16} =-1/2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+24}{2*8}=\frac{40}{16} =2+1/2 $

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