8x2-19x=2x2-x

Solution for 8x2-19x=2x2-x equation:

8x^2-19x=2x^2-x

We move all terms to the left:

8x^2-19x-(2x^2-x)=0

We get rid of parentheses

8x^2-2x^2-19x+x=0

We add all the numbers together, and all the variables

6x^2-18x=0

a = 6; b = -18; c = 0;
Δ = b2-4ac
Δ = -182-4·6·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-18}{2*6}=\frac{0}{12}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+18}{2*6}=\frac{36}{12}
=3
$