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8x^2-36x-20=0
a = 8; b = -36; c = -20;
Δ = b2-4ac
Δ = -362-4·8·(-20)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-44}{2*8}=\frac{-8}{16} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+44}{2*8}=\frac{80}{16} =5 $
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