8x2-48=0

Solution for 8x2-48=0 equation:

8x^2-48=0

a = 8; b = 0; c = -48;
Δ = b2-4ac
Δ = 02-4·8·(-48)
Δ = 1536
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1536}=\sqrt{256*6}=\sqrt{256}*\sqrt{6}=16\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{6}}{2*8}=\frac{0-16\sqrt{6}}{16}
=-\frac{16\sqrt{6}}{16}
=-\sqrt{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{6}}{2*8}=\frac{0+16\sqrt{6}}{16}
=\frac{16\sqrt{6}}{16}
=\sqrt{6}
$