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8x^2-62x+99=0
a = 8; b = -62; c = +99;
Δ = b2-4ac
Δ = -622-4·8·99
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-62)-26}{2*8}=\frac{36}{16} =2+1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-62)+26}{2*8}=\frac{88}{16} =5+1/2 $
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