8x2-6x+1=0

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Solution for 8x2-6x+1=0 equation: 



8x^2-6x+1=0

a = 8; b = -6; c = +1;
Δ = b2-4ac
Δ = -62-4·8·1
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2}{2*8}=\frac{4}{16}
=1/4
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2}{2*8}=\frac{8}{16}
=1/2
$

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