8x2-8x+2x=-3x2+x

Solution for 8x2-8x+2x=-3x2+x equation:

8x^2-8x+2x=-3x^2+x

We move all terms to the left:

8x^2-8x+2x-(-3x^2+x)=0

We add all the numbers together, and all the variables

8x^2-(-3x^2+x)-6x=0

We get rid of parentheses

8x^2+3x^2-x-6x=0

We add all the numbers together, and all the variables

11x^2-7x=0

a = 11; b = -7; c = 0;
Δ = b2-4ac
Δ = -72-4·11·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-7}{2*11}=\frac{0}{22}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+7}{2*11}=\frac{14}{22}
=7/11
$