8x2=6+22x

Solution for 8x2=6+22x equation:

8x^2=6+22x

We move all terms to the left:

8x^2-(6+22x)=0

We add all the numbers together, and all the variables

8x^2-(22x+6)=0

We get rid of parentheses

8x^2-22x-6=0

a = 8; b = -22; c = -6;
Δ = b2-4ac
Δ = -222-4·8·(-6)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-26}{2*8}=\frac{-4}{16}
=-1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+26}{2*8}=\frac{48}{16}
=3
$