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8x^2=68x+220
We move all terms to the left:
8x^2-(68x+220)=0
We get rid of parentheses
8x^2-68x-220=0
a = 8; b = -68; c = -220;
Δ = b2-4ac
Δ = -682-4·8·(-220)
Δ = 11664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{11664}=108$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-68)-108}{2*8}=\frac{-40}{16} =-2+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-68)+108}{2*8}=\frac{176}{16} =11 $
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