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8x^2=96
We move all terms to the left:
8x^2-(96)=0
a = 8; b = 0; c = -96;
Δ = b2-4ac
Δ = 02-4·8·(-96)
Δ = 3072
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3072}=\sqrt{1024*3}=\sqrt{1024}*\sqrt{3}=32\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32\sqrt{3}}{2*8}=\frac{0-32\sqrt{3}}{16} =-\frac{32\sqrt{3}}{16} =-2\sqrt{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32\sqrt{3}}{2*8}=\frac{0+32\sqrt{3}}{16} =\frac{32\sqrt{3}}{16} =2\sqrt{3} $
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