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8x^2x-(3x/7)=327
We move all terms to the left:
8x^2x-(3x/7)-(327)=0
We add all the numbers together, and all the variables
8x^2x-(+3x/7)-327=0
We get rid of parentheses
8x^2x-3x/7-327=0
We multiply all the terms by the denominator
8x^2x*7-3x-327*7=0
We add all the numbers together, and all the variables
8x^2x*7-3x-2289=0
Wy multiply elements
56x^2-3x-2289=0
a = 56; b = -3; c = -2289;
Δ = b2-4ac
Δ = -32-4·56·(-2289)
Δ = 512745
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{512745}}{2*56}=\frac{3-\sqrt{512745}}{112} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{512745}}{2*56}=\frac{3+\sqrt{512745}}{112} $
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