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8x=-(16x^2+1)
We move all terms to the left:
8x-(-(16x^2+1))=0
We calculate terms in parentheses: -(-(16x^2+1)), so:We get rid of parentheses
-(16x^2+1)
We get rid of parentheses
-16x^2-1
Back to the equation:
-(-16x^2-1)
16x^2+8x+1=0
a = 16; b = 8; c = +1;
Δ = b2-4ac
Δ = 82-4·16·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-8}{32}=-1/4$
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