8x=2(x-3)+4x

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Solution for 8x=2(x-3)+4x equation: 



8x=2(x-3)+4x

We move all terms to the left:

8x-(2(x-3)+4x)=0



We calculate terms in parentheses: -(2(x-3)+4x), so:

2(x-3)+4x

We add all the numbers together, and all the variables

4x+2(x-3)

We multiply parentheses

4x+2x-6

We add all the numbers together, and all the variables

6x-6

Back to the equation:

-(6x-6)



We get rid of parentheses

8x-6x+6=0

We add all the numbers together, and all the variables

2x+6=0

We move all terms containing x to the left, all other terms to the right

2x=-6

x=-6/2

x=-3

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