8x=3x+3-(1+x)-30

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Solution for 8x=3x+3-(1+x)-30 equation: 



8x=3x+3-(1+x)-30

We move all terms to the left:

8x-(3x+3-(1+x)-30)=0

We add all the numbers together, and all the variables

8x-(3x+3-(x+1)-30)=0



We calculate terms in parentheses: -(3x+3-(x+1)-30), so:

3x+3-(x+1)-30

determiningTheFunctionDomain
3x-(x+1)+3-30

We add all the numbers together, and all the variables

3x-(x+1)-27

We get rid of parentheses

3x-x-1-27

We add all the numbers together, and all the variables

2x-28

Back to the equation:

-(2x-28)



We get rid of parentheses

8x-2x+28=0

We add all the numbers together, and all the variables

6x+28=0

We move all terms containing x to the left, all other terms to the right

6x=-28

x=-28/6

x=-4+2/3

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