8x=3x+3-(1+x)-30

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Solution for 8x=3x+3-(1+x)-30 equation:



8x=3x+3-(1+x)-30
We move all terms to the left:
8x-(3x+3-(1+x)-30)=0
We add all the numbers together, and all the variables
8x-(3x+3-(x+1)-30)=0
We calculate terms in parentheses: -(3x+3-(x+1)-30), so:
3x+3-(x+1)-30
determiningTheFunctionDomain 3x-(x+1)+3-30
We add all the numbers together, and all the variables
3x-(x+1)-27
We get rid of parentheses
3x-x-1-27
We add all the numbers together, and all the variables
2x-28
Back to the equation:
-(2x-28)
We get rid of parentheses
8x-2x+28=0
We add all the numbers together, and all the variables
6x+28=0
We move all terms containing x to the left, all other terms to the right
6x=-28
x=-28/6
x=-4+2/3

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