8x=4(2x+1)+

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Solution for 8x=4(2x+1)+ equation: 



8x=4(2x+1)+

We move all terms to the left:

8x-(4(2x+1)+)=0



We calculate terms in parentheses: -(4(2x+1)+), so:

4(2x+1)+

We add all the numbers together, and all the variables

4(2x+1)

We multiply parentheses

8x+4

Back to the equation:

-(8x+4)



We get rid of parentheses

8x-8x-4=0

We add all the numbers together, and all the variables

-4!=0

There is no solution for this equation

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