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8y(-2y-3)=9
We move all terms to the left:
8y(-2y-3)-(9)=0
We multiply parentheses
-16y^2-24y-9=0
a = -16; b = -24; c = -9;
Δ = b2-4ac
Δ = -242-4·(-16)·(-9)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$y=\frac{-b}{2a}=\frac{24}{-32}=-3/4$
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