8y(y-0.5)=-28

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Solution for 8y(y-0.5)=-28 equation: 



8y(y-0.5)=-28

We move all terms to the left:

8y(y-0.5)-(-28)=0

We add all the numbers together, and all the variables

8y(y-0.5)+28=0

We multiply parentheses

8y^2-4y+28=0

a = 8; b = -4; c = +28;
Δ = b2-4ac
Δ = -42-4·8·28
Δ = -880
Delta is less than zero, so there is no solution for the equation

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