8y(y-8)=0

Solution for 8y(y-8)=0 equation:

8y(y-8)=0

We multiply parentheses

8y^2-64y=0

a = 8; b = -64; c = 0;
Δ = b2-4ac
Δ = -642-4·8·0
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-64}{2*8}=\frac{0}{16}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+64}{2*8}=\frac{128}{16}
=8
$