8y+(3y+1)=(8y+3y)+1

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Solution for 8y+(3y+1)=(8y+3y)+1 equation:


Simplifying
8y + (3y + 1) = (8y + 3y) + 1

Reorder the terms:
8y + (1 + 3y) = (8y + 3y) + 1

Remove parenthesis around (1 + 3y)
8y + 1 + 3y = (8y + 3y) + 1

Reorder the terms:
1 + 8y + 3y = (8y + 3y) + 1

Combine like terms: 8y + 3y = 11y
1 + 11y = (8y + 3y) + 1

Combine like terms: 8y + 3y = 11y
1 + 11y = (11y) + 1
1 + 11y = (11y) + 1

Reorder the terms:
1 + 11y = 1 + (11y)

Add '-1' to each side of the equation.
1 + -1 + 11y = 1 + -1 + (11y)

Combine like terms: 1 + -1 = 0
0 + 11y = 1 + -1 + (11y)
11y = 1 + -1 + (11y)

Combine like terms: 1 + -1 = 0
11y = 0 + (11y)
11y = (11y)

Add '-11y' to each side of the equation.
11y + -11y = (11y) + -11y

Combine like terms: 11y + -11y = 0
0 = (11y) + -11y

Combine like terms: (11y) + -11y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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