8y+1-3(-2y-1)=2(y-7)

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Solution for 8y+1-3(-2y-1)=2(y-7) equation: 



8y+1-3(-2y-1)=2(y-7)

We move all terms to the left:

8y+1-3(-2y-1)-(2(y-7))=0

We multiply parentheses

8y+6y-(2(y-7))+3+1=0



We calculate terms in parentheses: -(2(y-7)), so:

2(y-7)

We multiply parentheses

2y-14

Back to the equation:

-(2y-14)



We add all the numbers together, and all the variables

14y-(2y-14)+4=0

We get rid of parentheses

14y-2y+14+4=0

We add all the numbers together, and all the variables

12y+18=0

We move all terms containing y to the left, all other terms to the right

12y=-18

y=-18/12

y=-1+1/2

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