8y+1-3(-2y-2)=5(y-1)

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Solution for 8y+1-3(-2y-2)=5(y-1) equation: 



8y+1-3(-2y-2)=5(y-1)

We move all terms to the left:

8y+1-3(-2y-2)-(5(y-1))=0

We multiply parentheses

8y+6y-(5(y-1))+6+1=0



We calculate terms in parentheses: -(5(y-1)), so:

5(y-1)

We multiply parentheses

5y-5

Back to the equation:

-(5y-5)



We add all the numbers together, and all the variables

14y-(5y-5)+7=0

We get rid of parentheses

14y-5y+5+7=0

We add all the numbers together, and all the variables

9y+12=0

We move all terms containing y to the left, all other terms to the right

9y=-12

y=-12/9

y=-1+1/3

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