8y+1/y-3-6-y/3-y

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Solution for 8y+1/y-3-6-y/3-y equation:


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

8*y-(y/3)-y+1/y-6-3 = 0

20/3*y^1+1*y^-1-9*y^0 = 0

(20/3*y^2-9*y^1+1*y^0)/(y^1) = 0 // * y^2

y^1*(20/3*y^2-9*y^1+1*y^0) = 0

y^1

(20/3)*y^2-9*y+1 = 0

(20/3)*y^2-9*y+1 = 0

DELTA = (-9)^2-(1*4*(20/3))

DELTA = 163/3

DELTA > 0

y = ((163/3)^(1/2)+9)/(2*(20/3)) or y = (9-(163/3)^(1/2))/(2*(20/3))

y = 3/40*((163/3)^(1/2)+9) or y = 3/40*(9-(163/3)^(1/2))

y in { 3/40*(9-(163/3)^(1/2)), 3/40*((163/3)^(1/2)+9)}

y in { 3/40*(9-(163/3)^(1/2)), 3/40*((163/3)^(1/2)+9) }

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