8y+10=6(y-2)

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Solution for 8y+10=6(y-2) equation: 



8y+10=6(y-2)

We move all terms to the left:

8y+10-(6(y-2))=0



We calculate terms in parentheses: -(6(y-2)), so:

6(y-2)

We multiply parentheses

6y-12

Back to the equation:

-(6y-12)



We get rid of parentheses

8y-6y+12+10=0

We add all the numbers together, and all the variables

2y+22=0

We move all terms containing y to the left, all other terms to the right

2y=-22

y=-22/2

y=-11

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