8y+11=3(y-3)

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Solution for 8y+11=3(y-3) equation: 



8y+11=3(y-3)

We move all terms to the left:

8y+11-(3(y-3))=0



We calculate terms in parentheses: -(3(y-3)), so:

3(y-3)

We multiply parentheses

3y-9

Back to the equation:

-(3y-9)



We get rid of parentheses

8y-3y+9+11=0

We add all the numbers together, and all the variables

5y+20=0

We move all terms containing y to the left, all other terms to the right

5y=-20

y=-20/5

y=-4

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