8y+11=6y-40

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Solution for 8y+11=6y-40 equation: 



8y+11=6y-40

We move all terms to the left:

8y+11-(6y-40)=0

We get rid of parentheses

8y-6y+40+11=0

We add all the numbers together, and all the variables

2y+51=0

We move all terms containing y to the left, all other terms to the right

2y=-51

y=-51/2

y=-25+1/2

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