8y+14-1y=7(y+2)=

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Solution for 8y+14-1y=7(y+2)= equation: 



8y+14-1y=7(y+2)=

We move all terms to the left:

8y+14-1y-(7(y+2))=0

We add all the numbers together, and all the variables

7y-(7(y+2))+14=0



We calculate terms in parentheses: -(7(y+2)), so:

7(y+2)

We multiply parentheses

7y+14

Back to the equation:

-(7y+14)



We get rid of parentheses

7y-7y-14+14=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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