8y+16=-3(4-4/3y)

Solution for 8y+16=-3(4-4/3y) equation:

8y+16=-3(4-4/3y)

We move all terms to the left:

8y+16-(-3(4-4/3y))=0


Domain of the equation: 3y))!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

8y-(-3(-4/3y+4))+16=0

We multiply all the terms by the denominator


8y*3y+16*3y-4+4))-(-3(+4))=0

We add all the numbers together, and all the variables

8y*3y+16*3y-4+4))-(-34)=0

We add all the numbers together, and all the variables

8y*3y+16*3y=0

Wy multiply elements

24y^2+48y=0

a = 24; b = 48; c = 0;
Δ = b2-4ac
Δ = 482-4·24·0
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-48}{2*24}=\frac{-96}{48}
=-2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+48}{2*24}=\frac{0}{48}
=0
$