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8y+1=4(2y-3)
We move all terms to the left:
8y+1-(4(2y-3))=0
We calculate terms in parentheses: -(4(2y-3)), so:We get rid of parentheses
4(2y-3)
We multiply parentheses
8y-12
Back to the equation:
-(8y-12)
8y-8y+12+1=0
We add all the numbers together, and all the variables
13!=0
There is no solution for this equation
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