8y+2(y-5)=3(y+1)-2

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Solution for 8y+2(y-5)=3(y+1)-2 equation: 


Simplifying
8y + 2(y + -5) = 3(y + 1) + -2

Reorder the terms:
8y + 2(-5 + y) = 3(y + 1) + -2
8y + (-5 * 2 + y * 2) = 3(y + 1) + -2
8y + (-10 + 2y) = 3(y + 1) + -2

Reorder the terms:
-10 + 8y + 2y = 3(y + 1) + -2

Combine like terms: 8y + 2y = 10y
-10 + 10y = 3(y + 1) + -2

Reorder the terms:
-10 + 10y = 3(1 + y) + -2
-10 + 10y = (1 * 3 + y * 3) + -2
-10 + 10y = (3 + 3y) + -2

Reorder the terms:
-10 + 10y = 3 + -2 + 3y

Combine like terms: 3 + -2 = 1
-10 + 10y = 1 + 3y

Solving
-10 + 10y = 1 + 3y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3y' to each side of the equation.
-10 + 10y + -3y = 1 + 3y + -3y

Combine like terms: 10y + -3y = 7y
-10 + 7y = 1 + 3y + -3y

Combine like terms: 3y + -3y = 0
-10 + 7y = 1 + 0
-10 + 7y = 1

Add '10' to each side of the equation.
-10 + 10 + 7y = 1 + 10

Combine like terms: -10 + 10 = 0
0 + 7y = 1 + 10
7y = 1 + 10

Combine like terms: 1 + 10 = 11
7y = 11

Divide each side by '7'.
y = 1.571428571

Simplifying
y = 1.571428571

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