8y+2(y-5)=4(y+1)-3

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Solution for 8y+2(y-5)=4(y+1)-3 equation:


Simplifying
8y + 2(y + -5) = 4(y + 1) + -3

Reorder the terms:
8y + 2(-5 + y) = 4(y + 1) + -3
8y + (-5 * 2 + y * 2) = 4(y + 1) + -3
8y + (-10 + 2y) = 4(y + 1) + -3

Reorder the terms:
-10 + 8y + 2y = 4(y + 1) + -3

Combine like terms: 8y + 2y = 10y
-10 + 10y = 4(y + 1) + -3

Reorder the terms:
-10 + 10y = 4(1 + y) + -3
-10 + 10y = (1 * 4 + y * 4) + -3
-10 + 10y = (4 + 4y) + -3

Reorder the terms:
-10 + 10y = 4 + -3 + 4y

Combine like terms: 4 + -3 = 1
-10 + 10y = 1 + 4y

Solving
-10 + 10y = 1 + 4y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-4y' to each side of the equation.
-10 + 10y + -4y = 1 + 4y + -4y

Combine like terms: 10y + -4y = 6y
-10 + 6y = 1 + 4y + -4y

Combine like terms: 4y + -4y = 0
-10 + 6y = 1 + 0
-10 + 6y = 1

Add '10' to each side of the equation.
-10 + 10 + 6y = 1 + 10

Combine like terms: -10 + 10 = 0
0 + 6y = 1 + 10
6y = 1 + 10

Combine like terms: 1 + 10 = 11
6y = 11

Divide each side by '6'.
y = 1.833333333

Simplifying
y = 1.833333333

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