8y+20+2(y-5)=0

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Solution for 8y+20+2(y-5)=0 equation: 



8y+20+2(y-5)=0

We multiply parentheses

8y+2y-10+20=0

We add all the numbers together, and all the variables

10y+10=0

We move all terms containing y to the left, all other terms to the right

10y=-10

y=-10/10

y=-1

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